Two forces $F_{1}$ and $F_{2}$ of magnitude $5 N$ each inclined to each other at $60^{o}$ , act on a body. Find the resultant force acting on the body.

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Solution

$Step 1: Resultant force$
We know that, the resultant force of two vectors can be given as:
$R = \sqrt{F_{1}^{2} + F_{2}^{2} + 2 F_{1} F_{2} cos θ}$
$\Rightarrow R = \sqrt{{(5)}^{2} + {(5)}^{2} + 2 \times 5 \times 5 \times cos 60^{o}}$
$\Rightarrow R = \sqrt{75} = 8.66 N$
Hence, the resultant force acting on the body is $8.66 N$

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Two forces F1 and F2 of magnitude 5N each inclined to each other at 60o, act on a body. Find the resultant force acting on the body.

Step 1: Resultant forceWe know that, the resultant force of two vectors can be given as:R=√F21+F22+2F1F2cosθ⇒R=√(5)2+(5)2+2×5×5×cos60o⇒R=√75=8.66N Hence, the resultant force acting on the body is 8.66N

Two forces $F_{1}$ and $F_{2}$ of magnitude $5 N$ each inclined to each other at $60^{o}$ , act on a body. Find the resultant force acting on the body.