Two forces of 22 N and 10 N are applied on a block in opposite direction. Together they displace it by 6.5 metres. The net work done on the block is .

12 J

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90 J

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78 J

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Solution

The correct option is C 78 J
Two forces 22 N and 10 N are acting in opposite direction on the body.

The net force acting on the block =(22-10) N =12 N

Displacement of the body along the direction of the force is 6.5 m.

Net Work done
= Net force $\times$ total displacement
$= 12 \times 6.5 = 78$ J

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