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Question

Two forces of 3 N and 4 N are acting at a point such that the angle between them is 60 degrees. Find the resultant force.

A
Mangnitude of R=8 N and angle q=tan10.472
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B
Mangnitude of R=6 N and angle q=tan10.572
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C
Mangnitude of R=6.08 N and angle q=tan10.472
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D
Mangnitude of R=6.08 N and angle q=tan10.872
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Solution

The correct option is C Mangnitude of R=6.08 N and angle q=tan10.472
magnitude of resultant R is given as
= (3)2+(4)2+2×3×4cos60
=37=6.08 N
Direction of R is given by finding the angle q
Thus, tanq=3sin(60)4+3cos(60)=0.472
q=tan10.472

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