Two forces of 4 dyne and 3 dyne act upon a body. The resultant force on the body can only be:

between 3 and 4 dynes

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between 1 and 7 dynes

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more than 3 dynes

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more than 4 dynes

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Solution

The correct option is A between 1 and 7 dynes
Magnitude of resultant $\to R$ force will vary between its maximum & minimum value
$∣ ∣ ∣ {\to R}_{m a x} ∣ ∣ ∣ = 4 + 3 = 7 d y n e s ∣ ∣ ∣ {\to R}_{m i n} ∣ ∣ ∣ = 4 - 3 = 1 d y n e s$

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