Two forces, of equal magnitude P, are inclined at angle α with each other. If the resultant is also P, then the angle α (in degree) is
A
30°
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B
45°
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C
60°
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D
120°
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Solution
The correct option is D120° Let two forces be →F1 and →F2 having resultant →F1+→F2 Given, |→F1|=|→F2|=|→F1+→F2|=P ∴P=√P2+P2+2×P×Pcosα⇒P2=2P2+2P2cosθ⇒cosθ=−12⇒θ=120°