Two forces P and 2 P are inclined at 120- with each other- If their resultant makes an angle - with their bisector then the value of - in degree isA- 15-B- 30-C- 45-D- 60-

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Equation of Tangent at a Point (x,y) in Terms of f'(x)

Two forces P ...

Question

Two forces $P$ and $2 P$ are inclined at $120 °$ with each other. If their resultant makes an angle $α$ with their bisector then the value of $α$ (in degree) is

15 °

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30 °

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45 °

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60 °

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Solution

The correct option is B $30 °$
Let $β$ is the angle made by resultant with vector whose magnitude is $P$
$∴ tan β = \frac{2 P sin 120 °}{P + 2 P cos 120 °} = \frac{\sqrt{3}}{1 - 1}$
$\Rightarrow β = 90 °$
Now, Let the resulatant be $R$ and angle bisector be $B$ .

Hence $α = 90 ° - 60 ° = 30 °$

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Two forces P and 2P are inclined at 120° with each other. If their resultant makes an angle α with their bisector then the value of α (in degree) is

The correct option is B 30°Let β is the angle made by resultant with vector whose magnitude is P ∴tanβ=2Psin120°P+2Pcos120°=√31−1 ⇒β=90° Now, Let the resulatant be R and angle bisector be B. Hence α=90°−60°=30°

Two forces $P$ and $2 P$ are inclined at $120 °$ with each other. If their resultant makes an angle $α$ with their bisector then the value of $α$ (in degree) is