Question

Two forces which are perpendicular to each other, act on a body. The resultant force $F_1$ makes an angle of ${60}^o$ with one force. The magnitude of the other force is?

• A. $\sqrt{3}F/2$
• B. $F/\sqrt{2}$
• C. $F/2$
• D. $2F$

Answer 1

The correct option is A $\sqrt{3}F/2$

REF.Image.

$F_2=Fsin{60}^{\circ }$

$=\frac{\sqrt{3}F}{2}$ (A)