Two friends A and B are 30 km apart and they start simultaneously on motorcycles to meet each other. The speed of A is 3 times that of B. The distance between them decreases at the rate of 2 km per minute. Ten minutes after they start A's vehicle breaks down and A stops and waits for B to arrive. How much time after A started riding does B meet A ?

15

mins

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20

mins

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25

mins

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30

mins

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Solution

The correct option is D $30$ mins
Speed of $B = V k m / h r$
Speed of $A = 3 V k m / h r$
Given $4 V = 2 \times 60 k m / h r$
$\Rightarrow V = 30 k m / h r$
Distance covered by then after 10 min $= 2 \times 10 = 20 k m$
So remaining distance $= (30 - 20) k m = 10 k m$
Time taken by B to cover 10 km $= \frac{10}{\frac{30}{60}} = 20 m i n$
Total time $= 20 + 10 = 30 m i n$

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The correct option is D 30 minsSpeed of B=Vkm/hrSpeed of A=3Vkm/hr Given 4V=2×60km/hr⇒V=30km/hrDistance covered by then after 10 min =2×10=20kmSo remaining distance =(30−20)km=10kmTime taken by B to cover 10 km =103060=20minTotal time =20+10=30min