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Question

Two full turns of the circular scale of a screw gauge cover a distance of 1 mm on its main scale. The total number of divisions on the circular scale is 50. Further, it is found that the screw gauge has a zero error of -0.03 mm while measuring the diameter of a thin wire, a student notes the main scale reading of 3 mm and the number of circular scale divisions in line with the main scale as 35. The diameter of the wire is. [AIEEE-2008]

A
3.32 mm
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B
3.73 mm
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C
3.67 mm
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D
3.38 mm
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Solution

The correct option is D 3.38 mm
Diameter = M.S.R. + C.S.R x L.C + Z.E.
= 3 + 35 x (0.5/50) + 0.03 = 3.38 mm

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