wiz-icon
MyQuestionIcon
MyQuestionIcon
3
You visited us 3 times! Enjoying our articles? Unlock Full Access!
Question

Two full turns of the circular scale of a screw gauge covers a distance of 1 mm on its main scale. The total number of divisions on the circular scale is 50. Further, it is found that the screw gauge has a zero error of 0.03 mm. While measuring the diameter of a thin wire, a student notes the main scale reading of 3 mm and the number of circular scale divisions in line with the main scale as 35. The diameter of the wire is:

A
3.32 mm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
3.73 mm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
3.67 mm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
3.38 mm
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 3.38 mm
Least count of screw gauge =0.550 mm=0.01 mm
Reading = [Main scale reading + circular scale reading × L.C.] - (zero error)
=[3+35×0.01](0.03)=3.38 mm

flag
Suggest Corrections
thumbs-up
2
similar_icon
Similar questions
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Vernier Caliper and Screw Gauge
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon