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Question
Two full turns of the circular scale of a screw gauge covers a distance of 1 mm on its main scale. The total number of divisions on the circular scale is 50. Further, it is found that the screw gauge has a zero error of −0.03 mm. While measuring the diameter of a thin wire, a student notes the main scale reading of 3 mm and the number of circular scale divisions in line with the main scale as 35. The diameter of the wire is:
Two full turns of the circular scale of a screw gauge covers a distance of 1 mm on its main scale. The total number of divisions on the circular scale is 50. Further, it is found that the screw gauge has a zero error of −0.03 mm. While measuring the diameter of a thin wire, a student notes the main scale reading of 3 mm and the number of circular scale divisions in line with the main scale as 35. The diameter of the wire is:
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Solution
The correct option is D 3.38 mm
Least count of screw gauge =0.550 mm=0.01 mm
∴ Reading = [Main scale reading + circular scale reading × L.C.] - (zero error)
=[3+35×0.01]−(−0.03)=3.38 mm
Least count of screw gauge =0.550 mm=0.01 mm
∴ Reading = [Main scale reading + circular scale reading × L.C.] - (zero error)
=[3+35×0.01]−(−0.03)=3.38 mm
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