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Standard XII

Chemistry

Stoichiometric Calculations

Two gases A a...

Question

Two gases A and B having the same volume diffuse through a porous partition in $20$ and $10$ seconds respectively. The molecular mass of A is $49 u .$ Molecular mass of $B$ will be:

25.00 u

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50.00 u

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12.25 u

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6.50 u

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Solution

The correct option is C $12.25 u$
As we know,
$\frac{r_{A}}{r_{B}} = \sqrt{\frac{M_{B}}{M_{A}}} \Rightarrow \frac{v_{A}}{t_{A}} \times \frac{t_{B}}{v_{B}} = \sqrt{\frac{M_{B}}{M_{A}}}$
$\Rightarrow \frac{10}{20} = \sqrt{\frac{M_{B}}{49}} \Rightarrow \frac{1}{4} = \frac{M_{B}}{49} ∴ M_{B} = 49 / 4 = 12.25$

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Two gases A and B having the same volume diffuse through a porous partition in 20 and 10 seconds respectively. The molecular mass of A is 49 u. Molecular mass of B will be:

The correct option is C 12.25 uAs we know, rArB=√MBMA⇒vAtA×tBvB=√MBMA ⇒1020=√MB49⇒14=MB49∴MB=49/4=12.25

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