Two gases A and B having the same volume diffuse through a porous partition in 20 and 10 seconds respectively. The molecular mass of A is 49u. Molecular mass of B will be:
A
25.00u
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B
50.00u
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C
12.25u
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D
6.50u
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Solution
The correct option is C12.25u As we know, rArB=√MBMA⇒vAtA×tBvB=√MBMA ⇒1020=√MB49⇒14=MB49∴MB=49/4=12.25