Question

Two gases occupy two containers A and B the gas in A, of volume $0.10m^3$, exerts a pressure of 1.40 MPa and that in B of volume$0.15m^3$ exerts a pressure 0.7 MPa. The two containers are united by a tube of negligible volume and the gases are allowed to intermingle. Then it the temperature remains constant, the final pressure in the container will be (in MPa)

• A. 0.70
• B. 0.98
• C. 1.40
• D. 2.10

Answer 1

The correct option is B 0.98

As the quantity of gas remains constant ${\mu }_A+{\mu }_B=\mu$
$\frac{P_A{V}_A}{RT}+\frac{P_B{V}_B}{RT}=\frac{P(V_A+V_B)}{RT}\Rightarrow P=\frac{P_A{V}_A+P_B{V}_B}{V_A+V_B}=\frac{1.4\times 0.1+0.7\times 0.15}{0.1+0.15}\times P=0.98$ MPa.