Question

Two gases occupy two containers A and B. The gas in A of volume $0.11m^3$ exerts a pressure of 1.38 MPa. The gas in B of volume $0.16m^3$ exerts a pressure of 0.69 MPa. Two containers are united by a tube of negligible volume and the gases are allowed to intermingle. What is the final pressure in the container if the temperature remains constant ?

• A. $0.57MPa$
• B. $0.97MPa$
• C. $0.27MPa$
• D. $0.37MPa$

Answer 1

The correct option is B $0.97MPa$

Since after mixing, the pressure will be same throughout,

Also, $P_A{V}_A=n_{A}RT$

and $P_B{V}_B=n_{B}RT$

$P(V_A+V_B)=(n_A+n_B)RT=P_A{V}_A+P_B{V}_B$

Thus, $P=\frac{P_A{V}_A+P_A{V}_A}{V_A+V_B}$

$P=\frac{1.38\left(0.11\right)+0.69\left(0.16\right)}{0.11+0.16}MPa=0.97MPa$

Answer is $0.97MPa$