Question

Two genes R and Y are located very close on the chromosomal linkage map of the maize plant. When RRYY and rryy genotypes are hybridized, then F${}_2$ segregation will show:

• A. Higher number of the recombinant types
• B. Segregation in the expected 9 : 3 : 3: 1 ratio
• C. Segregation in 3: 1 ratio
• D. Higher number of the parental types

Answer 1

The correct option is D Higher number of the parental types

Law of independent assortment does not applicable when the genes of different character are linked. Here, the genes R and Y are closely linked which means the chance of segregation or recombination between the two genes will be less. The offsprings will show more of parental type. Hence, F${}_2$ segregation will show higher number of the parental types.