Question

Two genes R and y are located very close on the chromosome linkage map on maize plant. When RRYY and rryy genotypes are hybridised, then $F_2$ segregation will show

• A. Higher number of the recombinant types
• B. Segregation with expected 9:3:3:1 ratio
• C. Segeragation is 3:1 ratio
• D. Higher number of the parental types

Answer 1

Answer: (D)

Higher number of the parental types

When two genes are closely located on same chromosome there are more chances of the genes to undergo linkage. They will thus inherit together. It will result in increase in the number of parental types in F${}_2$ generation. Hence, the segregation shows more RRYY and rryy genotypes.

Thus, the correct answer is option D.