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Byju's Answer
Standard VIII
Mathematics
Properties of Orthogonality of two circles
Two given cir...
Question
Two given circles
x
2
+
y
2
+
a
x
+
b
y
+
c
=
0
and
x
2
+
y
2
+
d
x
+
e
y
+
f
=
0
will intersect each other orthogonally, only when
A
a+b+c = d+e+f
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B
ad+be = c+f
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C
2ad+2be = c+f
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Solution
From Condition for orthogonal intersection,
a
d
2
+
b
e
2
=
c
+
f
.
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Q.
Two given circles
x
2
+
y
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+
a
x
+
b
y
+
c
=
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and
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e
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=
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will intersect each other orthogonally, only when
Q.
Two given circles
x
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+
y
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+
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+
b
y
+
c
=
0
and
x
2
+
y
2
+
d
x
+
e
y
+
f
=
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will intersect each other orthogonally, only when
Q.
A
: If
x
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y
2
−
2
x
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y
+
k
=
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and
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y
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R
:
The circles
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2
+
y
2
+
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g
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+
2
f
y
+
c
=
0
and
x
2
+
y
2
+
2
g
′
x
+
2
f
′
y
+
c
′
=
0
cut each other orthogonally if
2
g
g
′
+
2
f
f
′
=
c
+
c
′
Q.
Find the equation to the circle which cuts orthogonally each of the circles
x
2
+
y
2
+
2
g
x
+
c
=
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,
x
2
+
y
2
+
2
g
′
x
+
c
=
0
, and
x
2
+
y
2
+
2
h
x
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k
y
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If the locus of centre of circle which cuts the circles
x
2
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y
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9
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0
and
x
2
+
y
2
−
4
x
+
6
y
+
4
=
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orthogonally is
a
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b
y
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0
then
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