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Byju's Answer
Standard IX
Mathematics
Properties of Orthogonality of Two Circles
Two given cir...
Question
Two given circles
x
2
+
y
2
+
a
x
+
b
y
+
c
=
0
and
x
2
+
y
2
+
d
x
+
e
y
+
f
=
0
will intersect each other orthogonally, only when
A
a+b+c = d+e+f
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B
ad+be = c+f
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C
2ad+2be = c+f
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Solution
From Condition for orthogonal intersection,
a
d
2
+
b
e
2
=
c
+
f
.
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Similar questions
Q.
Two given circles
x
2
+
y
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+
a
x
+
b
y
+
c
=
0
and
x
2
+
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2
+
d
x
+
e
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+
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=
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will intersect each other orthogonally, only when
Q.
Two given circles
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2
+
y
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+
a
x
+
b
y
+
c
=
0
and
x
2
+
y
2
+
d
x
+
e
y
+
f
=
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will intersect each other orthogonally, only when
Q.
Two given circles
x
2
+
y
2
+
a
x
+
b
y
+
c
=
0
and
x
2
+
y
2
+
d
x
+
e
y
+
f
=
0
will intersect each other orthogonally, only when
Q.
A
: If
x
2
+
y
2
−
2
x
+
3
y
+
k
=
0
and
x
2
+
y
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+
8
x
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6
y
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7
=
0
cut each other orthogonally, then
k
=
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R
:
The circles
x
2
+
y
2
+
2
g
x
+
2
f
y
+
c
=
0
and
x
2
+
y
2
+
2
g
′
x
+
2
f
′
y
+
c
′
=
0
cut each other orthogonally if
2
g
g
′
+
2
f
f
′
=
c
+
c
′
Q.
The circles
x
2
+
y
2
+
4
x
+
6
y
+
3
=
0
and
2
(
x
2
+
y
2
)
+
6
x
+
4
y
+
c
=
0
will cut orthogonally if
c
equals
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