Let the point S be (x1,y1) and the fixed point P be (h,k) and the axes be along OQ and OR and coordinates of OQ OR are (a,0) and (0,b) respectively.
As the parallelogram OQSR is completed. So the equation of line QR is
xa+yb=1
It also passes through the point P whose coordinates are (h,k)
⇒ha+kb=1
As the coordinates of S are (x1,y1)
hx1+ky1=1
Generalising the equation,
⇒hx+ky=1
is the required locus of S