Two glass bulbs A and B are connected by very small tube having a stop cock. Bulb A has a volume of 100 ml and contained the gas while bulb B was empty and has a volume of 150 ml. On opening the stop cock, the pressure of the gas in bulb A will fall down to___.

80%

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60%

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40%

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20%

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Solution

The correct option is C
40%

The total pressure $P_{T} = \frac{P_{1} V_{1} + P_{2} V_{2}}{V_{1} + V_{2}}$

$V_{1} = 100 m l V_{2} = 150 m l$

$P_{1} = P P_{2} = 0 (∵ i t i s e m p t y$ )

$P_{T} = \frac{100 \times P + 150 \times 0}{100 + 150} = \frac{100}{250} P = 0.4 P$

The pressure of the bulb ' A' will be fall down to 40%.

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Q. Two glass bulbs

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100 {c m}^{3}

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Two glass bulbs A and B are connected by very small tube having a stop cock. Bulb A has a volume of 100 ml and contained the gas while bulb B was empty and has a volume of 150 ml. On opening the stop cock, the pressure of the gas in bulb A will fall down to___.

Q. Two glass bulbs A and B are connected by a very small tube having a stop cock. Bulb A has a volume of 100

c m^{3}

and contained the gas, while bulb B was empty. On opening the stop cock, the pressure fell down 40%. The volume of the bulb B must be ?

Q. A glass bulb A and B are connected by a very small tube having a stop cock. Bulb A has a volume of 100 ml and contained the gas while bulb B was empty. On opening the stop cock, the pressure fell down to 40%. Assuming the temperature remains constant, the volume of the bulb B must be

Q. Two glass bulbs A and B at same temperature are connected by a very small tube having a stop cork. Bulb A has a volume of

100 c m^{3}

and contained the gas while bulb B was empty. On opening the stop cork, the pressure fell down to 20%. What is the volume of the bulb B?

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Two glass bulbs A and B are connected by very small tube having a stop cock. Bulb A has a volume of 100 ml and contained the gas while bulb B was empty and has a volume of 150 ml. On opening the stop cock, the pressure of the gas in bulb A will fall down to___.

The correct option is C 40% The total pressure PT=P1V1+P2V2V1+V2 V1=100 ml V2=150 ml P1=P P2=0(∵it is empty) PT=100×P+150×0100+150=100250P=0.4P The pressure of the bulb ' A' will be fall down to 40%.