Two glass bulbs $A$ and $B$ at same temperature are connected by a very small tube having a stop-cork. Bulb $A$ has a volume of $100 {c m}^{3}$ and contained the gas while bulb $B$ was empty and on opening the stop-cock the pressure dropped by $20$ %. The volume of the bulb $B$ must be

10 {c m}^{3}

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20 {c m}^{3}

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25 {c m}^{3}

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40 {c m}^{3}

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Solution

The correct option is C $25 {c m}^{3}$
R.E.F image
Given
Initial $P = P$
final Pressure $= \frac{4}{5} P$
$V_{0} = 100 c m^{3}$
$T \to$ fixed $P V = n R T$
$n_{g a s} \to$ fixed fixed
$R \to$ fixed
So, $P_{1} V_{1} = P_{2} V_{2}$
$P (V_{A}) = \frac{4}{5} P (V_{a} + V_{a})$
$P (100) = \frac{4}{5} P (100 + V_{8})$
$125 = 100 + V_{8}$
$V_{8} = 25 c m^{3}$

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Two glass bulbs A and B at same temperature are connected by a very small tube having a stop-cork. Bulb A has a volume of 100 cm3 and contained the gas while bulb B was empty and on opening the stop-cock the pressure dropped by 20%. The volume of the bulb B must be

The correct option is C 25 cm3R.E.F imageGiven Initial P=Pfinal Pressure =45PV0=100cm3T→ fixed PV=nRT ngas→ fixed fixedR→ fixedSo, P1V1=P2V2P(VA)=45P(Va+Va)P(100)=45P(100+V8)125=100+V8V8=25cm3

Two glass bulbs $A$ and $B$ at same temperature are connected by a very small tube having a stop-cork. Bulb $A$ has a volume of $100 {c m}^{3}$ and contained the gas while bulb $B$ was empty and on opening the stop-cock the pressure dropped by $20$ %. The volume of the bulb $B$ must be