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Question

Two glass bulbs K and L are connected by a very small tube having a stop-cork. Bulb K has a volume of 100 cm3 and contained the gas while bulb L was empty. On opening the stop-cork, the pressure fell down to 40%. The volume of the bulb L must be:

A
74 cm3
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B
125 cm3
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C
150 cm3
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D
250 cm3
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Solution

The correct option is C 150 cm3

Let volume of vessel to be VL
Pressure of K vessel P1
VK=100cm3
P1=P after opening of cork P2=P×40100P2=2P/5
nK(i)=(nK+nL)
P1VK=P2(VL+VK)
P(100)=2P5(VL+100)
500=2VL+200
VL=150cm3

993729_770761_ans_dcbea9a785ee4cc1b48d9a546ed949bb.jpg

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