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Question

Two glass bulbs of equal volume are connected by a narrow tube and filled with a gas at 0C and pressure of 76 cm of Hg. One of the bulb is then placed in a water bath maintained at 62C. What is the new value of the pressure inside the bulbs? The volume of the connecting tube is negligible.

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Solution

At first, at 273K
the mole in each bulb =ntotal2=12.P.2VRT=76V273×R
On heating second bulb, some mole of gas are transferred to another bulb until the pressure of both bulb become same.
n1=P×V273R and n2=PVR×335
ntotal=n1+n2
2×76V273R=P×V273R+PV335×RP=83.75 unit of Ag.

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