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Question

Two glass plates are separated by water. If the surface tension of water is 75 dyne/cm and the area of each plate wetted by water is 8cm2 and the distance between the plates is 1.2 cm, then the force applied to separate the two plates is

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Solution

Excess pressure inside a liquid is
P=T(1r1+1r2)
where, r1 and r2 is radius in perpendicular directions
Here,
P=T[2d+0][r2=]F=PA=2TdAF=2×75×81.2dyneF=1000dyne

990830_955616_ans_3e4f27d702f248f580c90d64aab18730.jpg

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