Two goods train each 5 0 0 - long- are running in opposite directions on parallel tracks- Their speeds are 4 5 - - - - - and 3 0 - - - - - respectively- What is the time taken by the slower train to pass the faster one-

The correct option is C 48 sec Relative speed = (45 + 30) km/hr = ( 75 ×5/18)m/s =( 125/6)m/s Distance covered = (500+500) m = 1000 m Required time = ( 1000 ×6 ...

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Standard VII

Mathematics

Relative Speed

Two goods tra...

Question

Two goods train each 500 m long, are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively.
What is the time taken by the slower train to pass the faster one?

12 sec

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24 sec

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48 sec

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60 sec

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36 sec

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Solution

The correct option is C
48 sec

Relative speed = (45 + 30) km/hr = $(75 \times \frac{5}{18})$ m/s = $(\frac{125}{6})$ m/s

Distance covered = (500+500) m = 1000 m

Required time = $(1000 \times \frac{6}{125})$ sec = 48 sec

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Two goods train each 500 m long, are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively. What is the time taken by the slower train to pass the faster one?

The correct option is C 48 sec Relative speed = (45 + 30) km/hr = (75×518)m/s =(1256)m/s Distance covered = (500+500) m = 1000 m Required time = (1000×6125)sec = 48 sec

Two goods train each 500 m long, are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively.
What is the time taken by the slower train to pass the faster one?

The correct option is C
48 sec

Relative speed = (45 + 30) km/hr = $(75 \times \frac{5}{18})$ m/s = $(\frac{125}{6})$ m/s

Distance covered = (500+500) m = 1000 m

Required time = $(1000 \times \frac{6}{125})$ sec = 48 sec