Two goods train each $500$ m long are running in opposite directions on parallel tracks. Their speeds are $45$ km/hr and $30$ km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one.

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Solution

Relative speed = (45 + 30) km/hr
= $(75 \times \frac{5}{18})$ m/sec = $(\frac{125}{6})$ m/sec
Distance covered = (500 + 500) m = 1000 m
Required time = $(1000 \times \frac{6}{125})$ sec = 48 sec

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Two goods train each 500 m long are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one.

Relative speed = (45 + 30) km/hr= (75×518) m/sec = (1256) m/secDistance covered = (500 + 500) m = 1000 mRequired time = (1000×6125) sec = 48 sec

Two goods train each $500$ m long are running in opposite directions on parallel tracks. Their speeds are $45$ km/hr and $30$ km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one.

Relative speed = (45 + 30) km/hr
= $(75 \times \frac{5}{18})$ m/sec = $(\frac{125}{6})$ m/sec
Distance covered = (500 + 500) m = 1000 m
Required time = $(1000 \times \frac{6}{125})$ sec = 48 sec