1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# Two guns A and B can fire bullets at speed of 3 km/s and 4 km/s respectively. , They are fired in all possible directions, from a point on the horizontal ground. The ratio of maximum area covered by the fired bullets on the ground will be:

A
34
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
916
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
81256
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## The correct option is C 81256 When the guns fire bullets at some angle θ,it will follow the prabolic path for a projectile. Range of the projectile is given by: R=u2sin2θg.......(1) ∴ Maximum area of fired bullets will correspond to area of circle with radius equal to maximum range (r=Rmax). ⇒Range will be maximum for sin2θ=1 i.e θ=45∘ i.e,Rmax=u2g Ratio of maximum area; ⇒(Maximum Area)A(Maximum Area)B=π(Rmax)2Aπ(Rmax)2B=u4Ag2u4Bg2=u4Au4B ∴(Maximum Area)A(Maximum Area)B=(3)4(4)4=81256

Suggest Corrections
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program