Two guns were fired from the same place at an interval of 10 minutes and 30 seconds but a person in the train approaching the place hears the second shot 10 minutes after the first.The speed of the train(in km/hr)supposing that speed travels at 330 metres per second.

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Solution

Let the speed of the train be $x$ m/sec. Then distance traveled by train in $10$ min $=$ Distance traveled by sound in $30$ sec.
$\Rightarrow x \times 10 \times 60 = 330 \times 30$
$\Rightarrow x = \frac{330 \times 30}{10 \times 60} = 16.5$
$∴$ Speed of the train $= 16.5$ m/sec $= 16.5 \times \frac{18}{5} = 59.4$ km/hr.

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Two guns were fired from the same place at an interval of 10 minutes and 30 seconds but a person in the train approaching the place hears the second shot 10 minutes after the first.The speed of the train(in km/hr)supposing that speed travels at 330 metres per second.

Let the speed of the train be x m/sec. Then distance traveled by train in 10 min = Distance traveled by sound in 30 sec.⇒x×10×60=330×30⇒x=330×3010×60=16.5∴ Speed of the train =16.5 m/sec =16.5×185=59.4 km/hr.