Two hails stones with radii in the ratio of 1 : 2 fall from a great height through the atmosphere. Then the ratio of their momentum after they have attained terminal velocity is:

1 : 32

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1 : 16

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1 : 8

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1 : 4

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Solution

The correct option is A
1 : 32

$\frac{v_{1}}{v_{2}} = \frac{r_{1}^{2}}{r_{2}^{2}}$

and $\frac{p_{1}}{p_{2}} = \frac{m_{1} v_{1}}{m_{2} v_{2}} = \frac{r_{1}^{5}}{r_{2}^{5}}$

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Two hails stones with radii in the ratio of 1 : 2 fall from a great height through the atmosphere. Then the ratio of their momentum after they have attained terminal velocity is:

The correct option is A 1 : 32 v1v2=r21r22 and p1p2=m1v1m2v2=r51r52

The correct option is A
1 : 32

$\frac{v_{1}}{v_{2}} = \frac{r_{1}^{2}}{r_{2}^{2}}$

and $\frac{p_{1}}{p_{2}} = \frac{m_{1} v_{1}}{m_{2} v_{2}} = \frac{r_{1}^{5}}{r_{2}^{5}}$