CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
5
You visited us 5 times! Enjoying our articles? Unlock Full Access!
Question

Two identical blocks A and B of mass m joined together with a massless spring as shown in the figure are placed on a smooth surface. If the block A moves with an acceleration a0, then the acceleration of the block B is

117615.png

A
a0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
a0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
fma0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
fm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C fma0
Mass of the System ( spring + blocks )=2m since the spring is massless.

Acceleration of the CM=acm=f2m

acm=m1a1+m2a2m1+m2 ........(1)

a1=a0
Substituting acm and a1 in (1) we get,

f2m=ma0+ma22m

a2=fma0;

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Centre of Mass in Galileo's World
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon