Two identical bricks of length L are piled one on top of the other on a table as shown in the figure. The maximum distance S the top brick can overhang the table with the system still balanced is :
A
12L
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B
23L
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C
34L
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D
78L
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Solution
The correct option is C34L The center of mass of the set of bricks must be above or to the left of the point of support for the system of be balanced.
The center of mass of the upper brick needs to be above the right end of lower brick. The center of upper brick is at a distance of L/2 from its right end.
The distance center of mass of both the books from the right edge of upper brick=(mL/2)+(mL)2m=3L4=S.