Two identical capacitors 1 and 2 are connected in series to a battery as shown in the figure- Capacitor 2 contains a dielectric slab of dielectric constant slab of dielectric constant K as shown- Q 1 and Q 2 are the charges stored in the capacitors- Now the dielectric slab is removed and the corresponding charges areA- Q2-Q2-K-1-2B- Q2-O2-K-1-2 KC- Q1-O1-K-1-KD- Q1-Q1-K-2

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Byju's Answer

Standard XII

Physics

Parallel and Series Combination of Capacitors

Two identical...

Question

Two identical capacitors 1 and 2 are connected in series to a battery as shown in the figure. Capacitor 2 contains a dielectric slab of dielectric constant slab of dielectric constant K as shown. Q₁ and Q₂ are the charges stored in the capacitors. Now the dielectric slab is removed and the corresponding charges are then:

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Solution

The correct option is C
Let C be the capacity without slab. Then after removing the slab, net capacity is C/2

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Similar questions

Q. Two identical capacitors 1 and 2 are connected in series to a battery as shown in figure. Capacitor 2 contains a dielectric slab of constant K.

Q_{1}

and

Q_{2}

are the charges stored in

C_{1}

and

C_{2}

. Now, the dielectric slab is removed and the corresponding charges are

Q_{1}^{'}

Q_{2}^{'}

. Then

Two identical capacitors 1 and 2 are connected in series to a battery as shown in the figure. Capacitor 2 contains a dielectric slab of dielectric constant slab of dielectric constant K as shown. Q₁ and Q₂ are the charges stored in the capacitors. Now the dielectric slab is removed and the corresponding charges are then:

Q. Two identical capacitors 1 and 2 connected in series to a battery as shown in figure. Capacitor 2 contains a dielectric slab of dielectric constant K as shown. If

Q_{1}

is the charge on each capacitor before removing the slab and

Q_{2}

is the charge on each capacitor after
moving the slab, then the correct relation between

Q_{1}

and

Q_{2}

is.

Two identical capacitors 1 and 2 are connected in series. The capacitor 2 contains a dielectric slab of constant $K$ as show. They are connected to as battery of emf $V_{0}$ volts. The dielectric slab is then removed. Let $Q_{1}$ and $Q_{2}$ be the charge stored in the capacitors before removing the slab and ${Q_{1}}^{'},$ and ${Q_{2}}^{'}$ be the values after removing the slab. Then:

Q. Two identical sized capacitors

C_{1}

and

C_{2}

are connected to a battery in series. A dielectric slab of dielectric constant

K = 2

is filled in the half region of both the capacitors as shown in figure.

(C \to

capacitance,

q \to

charge stored,

U \to

energy stored

)

Match the following column:

Column I	Column II
$(A)$ $\frac{C_{1}}{C_{2}}$	$(p)$ $8 / 9$ $(q)$ $4 / 9$ $(r)$ $9 / 8$ $(s)$ None of these
$(B)$ $\frac{q_{1}}{q_{2}}$
$(C)$ $\frac{U_{1}}{U_{2}}$

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The correct option is C Let C be the capacity without slab. Then after removing the slab, net capacity is C/2

The correct option is C
Let C be the capacity without slab. Then after removing the slab, net capacity is C/2