Two identical capacitors are connected in series with a source of potential V. If Q is the charge on one of the capacitors, the capacitance of each capacitor is:
A
Q/2V
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2Q/V
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
Q/V
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B 2Q/V In series connection charge on each capacitor would be constant also equivalent capacitance in series c′=C2 [ following 1c′=1c1+1c2] and voltage V is applied across it so,from capacitive law,Q=c′v⇒Q=CV2⇒C=2QV