Two identical capacitors are joined in parallel and charged to a potential V. Then these are separated and connected in series with the positive plate of one connected to the negative ofthe other. Then the

the potential difference between the plates becomes 2V

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the energy stored in the system increases

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the charges on the free plates are enhanced

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the charges on the plates connected together are destroyed

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Solution

The correct option is A the potential difference between the plates becomes 2V
When they are connected in parallel, each capacitor will have a potential V. When they are joined in series having each of potential V, then total potential across the two extreme plates of the capacitor = V + V = 2V.

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Two identical capacitors are joined in parallel and charged to a potential V. Then these are separated and connected in series with the positive plate of one connected to the negative ofthe other. Then the

The correct option is A the potential difference between the plates becomes 2VWhen they are connected in parallel, each capacitor will have a potential V. When they are joined in series having each of potential V, then total potential across the two extreme plates of the capacitor = V + V = 2V.

The correct option is A the potential difference between the plates becomes 2V
When they are connected in parallel, each capacitor will have a potential V. When they are joined in series having each of potential V, then total potential across the two extreme plates of the capacitor = V + V = 2V.