Two identical capacitors each of capacitance C are charged to the same potential V and are connected in two circuits (i) and (ii) at t=0 as shown. The charged on the capacitor at t=CR are :
A
CVe,CVe
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
CV,CV
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
VCe,VC
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
VC,VCe
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is CVCe,VC For the circuit (i), diode has higher voltage at p-side, so it is forward-biased and acts as short.
Thus capacitor discharge through capacitor.
q=q0e−t/RC=CVe−t/RC
at t=RC,q=CVe−CR/CR=CV/e
For the circuit (ii), diode has higher voltage on the n-side, so it is reversed-biased and acts as open circuit.
So the capacitor is isolated and its charge stays the same.