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Byju's Answer

Standard XII

Physics

Reverse Bias

Two identical...

Question

Two identical capacitors each of capacitance C are charged to the same potential V and are connected in two circuits (i) and (ii) at t=0 as shown. The charged on the capacitor at t=CR are :

\frac{C V}{e}, \frac{C V}{e}

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C V, C V

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\frac{V C}{e}, V C

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V C, \frac{V C}{e}

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Solution

The correct option is C $\frac{V C}{e}, V C$
For the circuit (i), diode has higher voltage at p-side, so it is forward-biased and acts as short.
Thus capacitor discharge through capacitor.
$q = q_{0} e^{- t / R C} = C V e^{- t / R C}$
at $t = R C, q = C V e^{- C R / C R} = C V / e$

For the circuit (ii), diode has higher voltage on the n-side, so it is reversed-biased and acts as open circuit.
So the capacitor is isolated and its charge stays the same.
So $q = C V$
Option C is correct.

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