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Question

Two identical capacitors, have the same capacitance C. One of them is charged to potential V1 and the other to V2. The negative ends of the capacitors are connected together. When the positive ends are also connected, the decrease in energy of the combined system is:

A
14C(V12V22)
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B
14C(V21+V22)
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C
14C (V1V2)2
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D
14C (V1+V2)2
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Solution

The correct option is B 14C (V1V2)2

Refer to image

For Initial E=12CV21+12CV22

For Final E=2×12C(V1+V22)2

ΔE=12CV21+12CV222×12C(V1+V22)2

ΔE=14C(V1V2)2


1106203_1010609_ans_1876ae0314e8487cb5335165896f2a56.PNG

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