Two identical cells of emf E and internal resistance r are connected in parallel with an external resistance R. To get maximum power developed across R, the value of R is

R = r / 2

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R = r

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r = r / 3

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R = 2 r

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Solution

The correct option is A $R = r / 2$
As two cell are connected in parallel combination.
So, their internal resistance = $\frac{r}{2}$
From maximum power theorem
internal resistance = external resistance
$\frac{r}{2} = R$

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Two identical cells of emf E and internal resistance r are connected in parallel with an external resistance R. To get maximum power developed across R, the value of R is

The correct option is A R=r/2As two cell are connected in parallel combination.So, their internal resistance = r2From maximum power theoreminternal resistance = external resistancer2=R

The correct option is A $R = r / 2$
As two cell are connected in parallel combination.
So, their internal resistance = $\frac{r}{2}$
From maximum power theorem
internal resistance = external resistance
$\frac{r}{2} = R$