wiz-icon
MyQuestionIcon
MyQuestionIcon
6
You visited us 6 times! Enjoying our articles? Unlock Full Access!
Question

Two identical charged spheres suspended from a common point by two massless strings of lengths l, are initially at a distance d(d<<l) apart because of their mutual repulsion. The charges begin to leak from both the spheres at a constant rate. As a result, the spheres approach each other with a velocity v. Which of the following correctly represent the variation of v as a function of the distance x between the spheres.

A
vx12
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
vx1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
vx12
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
vx12
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C vx12

From figure,

Tcosθ=mg (1)
Tsinθ=kq2x2 (2)

From eqns. (1) and (2),

tanθ=kq2x2mg

Since d<<l so will be x<<l. so θ is small,
tan θsin θ=x2l
x2l=kq2x2mgq2=x3mg2lk

qx32

Differentiating with respect to time on both sides we get,

dqdt32xdxdt

dqdt32xv

From the data given in the question,

dqdt=constant

v1x

Hence, option (a) is the correct answer.

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon