Two identical coils have a common centre and their planes are at right angles to each other and carry equal currents. If the magnitude of the induction field at the centre due to one of the coil is ‘B’. then the resultant magnetic induction field due to combination is

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\sqrt{2} B

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{B}{\sqrt{2}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $\sqrt{2} B$
$\Rightarrow B_{n e t} = \sqrt{B_{1}^{2} + B_{2}^{2} + 0}$
$\Rightarrow B_{n e t} = \sqrt{2} B$ .

Suggest Corrections

Similar questions

Q. Two identical coils carry equal currents have a common centre and their planes are at right angles to each other. The ratio of the magnitude of the resultant magnetic field at the centre and the field due to one coil is :

Two similar coils of radius R are lying concentricaly with their planes at right angles to each other. The current flowing In them are l and 2l, respectively. The resultant magnetic field induction at the centre will be?

Q. Two identical concentric coils

X

and

Y

carrying currents in the ratio

1 : 2

are arranged in mutually perpendicular planes. If the magnetic field due to coil

X

B

the net field at their common centre is:

Q. Two identical coils of

5

turns each carry

1 A

and

2 A

current respectively. Assume that they have common centre with their planes parallel to each other. If their radius is

1 m

each and the direction of flow of current in the coils are in opposite directions, then the magnetic field produced on its axial line at a distance of

\sqrt{3} m

, from the common centre is (in tesla).

Join BYJU'S Learning Program

Two identical coils have a common centre and their planes are at right angles to each other and carry equal currents. If the magnitude of the induction field at the centre due to one of the coil is ‘B’. then the resultant magnetic induction field due to combination is

The correct option is B √2B⇒Bnet=√B21+B22+0⇒Bnet=√2B.

The correct option is B $\sqrt{2} B$
$\Rightarrow B_{n e t} = \sqrt{B_{1}^{2} + B_{2}^{2} + 0}$
$\Rightarrow B_{n e t} = \sqrt{2} B$ .