Question

# Two identical conducting balls having positive charges q1 and q2 are separated by a distance r. If they are made to touch each other and then separated to the same distance, the force between them will be

A
less than before
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B
same as before
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C
more than before
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D
zero
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Solution

## The correct option is B more than beforeIf they are made to touch each other, the electrostatic conduction will occur. As a result the total charge will get distributed equally on both the balls because both the balls are identical in nature. Initially, F∝q1q2 (Since F=kq1q2r2)Now after making contact, charge on each ball will become Q1=Q2=q1+q22Now, F′∝(q1+q22)2(Because they are separated to the same distance) From above we can say that F′>F

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