You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Kinetic Theory of Gases

Two identical...

Question

Two identical containers are filled with a gas. The first is filled with methane ( ${C H}_{4}$ ) and the second with helium.
Which gas would effuse more rapidly out of its container and how many times faster would the process take place?
Assume all conditions are equal except the identity of the gases in the two containers.

H e, 4 \times

faster

No worries! We‘ve got your back. Try BYJU‘S free classes today!

{C H}_{4}, 4 \times

faster

No worries! We‘ve got your back. Try BYJU‘S free classes today!

H e, 2 \times

faster

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

{C H}_{4}, 2 \times

faster

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $H e, 2 \times$ faster
We know, diffusion rate $α^{1 / \sqrt{M}}$
(inversely proportional)
for $H e$ , $M = 4$
diffusion rate $= \frac{K}{\sqrt{4}} = \frac{K}{2}$
for ${C H}_{4}$ , $M = 16$
diffusion rate $= \frac{K}{\sqrt{16}} = \frac{K}{4}$
Hence $H e$ is $2$ times faster than ${C H}_{4}$ .

Suggest Corrections

Similar questions

Q. A gaseous mixture of

H e

C H_{4}

gases with mole ratio 2: 1 respectively are placed in a container and allowed to effuse through a small orifice.

X

m l

of the

H e

gas effuses in 5 seconds. The time required to effuse the same volume of

C H_{4}

gas is:

Q. A gaseous mixture of

H e

C H_{4}

gases with mole ratio 2 : 1 respectively is placed in a container and allowed to effuse through a small orifice.

X m l

of the

H e

gas effuses in 5 seconds. The time required to effuse same volume of

C H_{4}

gas is:

Q. Two flasks

A

and

B

have equal mass and volume.

A

contains

H_{2}

gas,

B

contains

C H_{4}

gas maintained at 300

K

and

B

at 600

K

respectively. Identify the flask in which molecules are moving faster.

[Assuming ideal behaviors for both the gases]

Q. Which of the following options is/are correct with respect to

C H_{4}

and

S O_{2}

? (Equal mass of

C H_{4}

and

S O_{2}

are contained in a 2 L container at same temperature)

Two containers A and B have the same volume. Container 'A' contains 5 mole of oxygen gas. Container 'B' contains 3 moles of He gas and 2 mole of $C H_{4}$ gas. Both the containers are separately kept in vaccum at the same temperature. Both the containers have very small orifices of the same area through which the gases leak out. The rate of diffusion of $O_{2}$ is how many times the rate of diffusion of He and $C H_{4}$ mixture.

Join BYJU'S Learning Program

The correct option is C He,2× fasterWe know, diffusion rate α1/√M (inversely proportional)for He, M=4diffusion rate =K√4=K2for CH4, M=16diffusion rate =K√16=K4Hence He is 2 times faster than CH4.