Question

Two identical containers each of volume V${}_0$ are joined by a small pipe. The containers contain identical gases at temperature T${}_0$ and pressure P${}_0$. One container is heated to temperature 2T${}_0$ while maintaining the other at the same temperature. The common pressure of the gas is P and n is the number of moles of gas in container at temperature 2T${}_0$.

• A. $P=2P_0$
• B. $P=\frac{4}{3}{P}_0$
• C. $n=\frac{2P_0{V}_0}{3R{T}_0}$
• D. $n=\frac{3P_0{V}_0}{2R{T}_0}$

Answer 1

The correct option is B $P=\frac{4}{3}{P}_0$

Since the total number of moles in the system remains the same before and after heating,

$\frac{P_0{V}_0}{T_0}+\frac{P_0{V}_0}{T_0}=\frac{P{V}_0}{T_0}+\frac{P{V}_0}{2T_0}$

$⟹P=\frac{4}{3}{P}_0$