Question

Two identical cubes each of volume $64$ $c{m}^3$ are joined together end to end. What is the surface area of the resulting cuboid?

Answer 1

Volume of cube$=($ edge ${)}^3=64$
$\Rightarrow$edge$=4$ cm
Sice the cubes are joined together end to end length will get doubled. Breadth and height will not be altered.
$\Rightarrow$ Dimensions of the cuboid will be $l=8,b=h=4$
Surface area of cubiod $=2(lb+bh+lh)$
$=2(32+16+32)$
$=160$ $c{m}^2$