Two identical glass bulbs are interconnected by a thin glass tube. A gas is filled in these bulbs at N.T.P. If one bulb is placed in ice and another bulb is placed in hot bath, then the pressure of the gas becomes 1.5 times. The temperature of hot bath will be
546°C
The number of moles of the gas remains constant
n1+n2=P(V1+V2)RT=1×2VR×273After placing them in the bath.n1+n2=1.5VR×273+1.5VRTHence, 1×2VR×273=1.5VR×273+1.5VRT⇒T=8191K=546∘C