Question

Two identical glass bulbs are interconnected by a thin glass tube at $0^{\circ }C$. A gas is filled at N.T.P. in these bulb is placed in ice and another bulb is placed in hot bath, then the pressure of the gas becomes $1.5times$. The temperature of hot bath will be

• A. ${100}^{\circ }$
• B. ${182}^{\circ }C$
• C. ${256}^{\circ }C$
• D. ${546}^{\circ }C$

Answer 1

The correct option is D ${546}^{\circ }C$

Quantity of gas in these bulbs is constant i.e,

Initial no. of moles in both bulb $=$ final no. of moles

$\Rightarrow n_1+n_2=n_1^{{}^{\prime }}+n_2^{{}^{\prime }}$

$\Rightarrow \frac{PV}{R\left(273\right)}+\frac{PV}{R\left(273\right)}=\frac{1.5PV}{R\left(273\right)}+\frac{1.5PV}{R\left(T\right)}$

$\Rightarrow \frac{2}{273}=\frac{1.5}{273}+\frac{1.5}{T}$

$\Rightarrow T=819K$

$=546°C$

Hence, the answer is $546°C.$