Question

Two identical inductances carry currents that vary with time according to linear law (as shown in figure). In which of the two inductances is the self-induced e.m.f. greater ?

• A. $1$
• B. $2$
• C. equal in $1$ and $2$
• D. data are insufficient to decide

Answer 1

The correct option is A $1$


Self-induced emf is $e=-L\frac{di}{dt}$
from figure,
${\theta }_1>{\theta }_2$

$\therefore (-\frac{d{I}_1}{dt})>(-\frac{d{I}_2}{dt})$

$\therefore e_1>e_2$