Question

Two identical lead balls are immersed into a measuring jar containing water, the level of water raises from 26 cm${}^3$ to 38 cm${}^3$. If one of the above lead ball and another metallic ball are immersed simultaneously than level of water in measuring jar rises from 26 cm${}^3$ to 36 cm${}^3$. Find the volume of the lead ball and metallic ball.

• A. 4$c{m}^3$
• B. 8$c{m}^3$
• C. 2$c{m}^3$
• D. 5$c{m}^3$

Answer 1

The correct option is A 4$c{m}^3$

Volume of 2 lead balls $=(38-26)c{m}^3$
$=12c{m}^3$
Volume of 1 lead ball $=6c{m}^3$
Volume of 1 lead ball and metallic ball $=36c{m}^3-26c{m}^3=10c{m}^3$
$\therefore$ Volume of metallic ball $=10c{m}^3-6c{m}^3=4c{m}^3$