Two identical magnets are placed perpendicular to each other with their unlike poles in contact. If magnetic moment of each magnet is $M$ , the resultant magnetic moment is:

2 M

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M

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\sqrt{2} M

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\frac{M}{\sqrt{2}}

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Solution

The correct option is C $\sqrt{2} M$
$M = \sqrt{M_{1}^{2} + M_{2}^{2} + M_{1} M_{2} cos θ}$
$M = \sqrt{M^{2} + M^{2} + 2 M^{2} cos 90^{o}}$ (angle between the vectors would be $90^{o}$ )
$M = \sqrt{2} M$

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Two identical magnets are placed perpendicular to each other with their unlike poles in contact. If magnetic moment of each magnet is M, the resultant magnetic moment is:

The correct option is C √2MM=√M21+M22+M1M2cosθM=√M2+M2+2M2cos90o (angle between the vectors would be 90o )M=√2M

Two identical magnets are placed perpendicular to each other with their unlike poles in contact. If magnetic moment of each magnet is $M$ , the resultant magnetic moment is:

The correct option is C $\sqrt{2} M$
$M = \sqrt{M_{1}^{2} + M_{2}^{2} + M_{1} M_{2} cos θ}$
$M = \sqrt{M^{2} + M^{2} + 2 M^{2} cos 90^{o}}$ (angle between the vectors would be $90^{o}$ )
$M = \sqrt{2} M$