wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Two identical metal plates show photoelectric effect by a light of wavelength λA falls on plate A and λB on plate B (λA=2λB). The maximum kinetic energy is


A

2KA=KB

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

KA<KB2

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C

KA=2KB

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

KA=KB2

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B

KA<KB2


hcλ=W0+KmaxhcλA=W0+KA . . .. . . .(i)
and hcλB=W0+KB . . . .. . . . .(ii)
Subtracting (i) from (ii),
hc[1λB1λA]=KBKA
hc[1λB12λB]=KBKAhc2λB=KBKA . . . . .(iii)
From (ii) and (iii), 2KB2KA=W0+KB
KB2KA=W0
KA=KB2W02 which gives KA<KB2


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Stopping Potential Revisited
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon